For the given electrolyte A x B y . The degree of dissociation 'α' can be given as:
Chemistry · JEE Main · NTA Exams — Solutions
For the given electrolyte AxBy. The degree of dissociation 'α' can be given as:
- \(\mathbf{x}=\frac{i-1}{(\mathbf{x}+\mathbf{y}-1)}\)
- \(i=[1-\mathbf{I}]+\mathbf{x} \mathbf{I}+\mathbf{y} \mathbf{I}\)
- \(\mathbf{x}=\frac{1-i}{(1-\mathbf{x}-\mathrm{y})}\)
- Either of these
Answer
(A) x = i-1 ( x + y -1)
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