A uniform chain has a mass M and length L. It is placed on a frictionless table with…
Physics · JEE Advanced · NTA Exams — Work, Energy and Power
A uniform chain has a mass M and length L. It is placed on a frictionless table with length l0 hanging over the edge. The chain begins to slide down. Then, the speed v with which the end slides down from the edge is given by:
- \(v=\sqrt{\frac{g}{L}\left(L+l_{0}\right)}\)
- \(v=\sqrt{\frac{g}{L}\left(L-l_{0}\right)}\)
- \(v=\sqrt{\frac{g}{L}\left(L^{2}-l_{0}^{2}\right)}\)
- \(v=\sqrt{2 g\left(L-l_{0}\right)}\)
Answer
(C) v= g L (L^ 2 -l_ 0 ^ 2 )
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