A constant power P is applied to a particle of mass m. The distance travelled by the…

Physics · JEE Advanced · NTA Exams — Work, Energy and Power

A constant power P is applied to a particle of mass m. The distance travelled by the particle when its velocity increases from v1 to v2 is (neglect friction)
  1. \(\frac{3 P}{m}\left(v_{2}^{2}-v_{1}^{2}\right)\)
  2. \(\frac{m}{3 P}\left(v_{2}-v_{1}\right)\)
  3. \(\frac{m}{3 P}\left(v_{2}^{3}-v_{1}^{3}\right)\)
  4. \(\frac{m}{3 P}\left(v_{2}^{2}-v_{1}^{2}\right)\)

Answer

(C) m 3 P (v_ 2 ^ 3 -v_ 1 ^ 3 )

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