The vector i +x j +3 k is rotated through an angle θ and doubled in magnitude, then it…
Mathematics · JEE Main · NTA Exams — Vector Algebra
The vector \(\hat{i}+x \hat{j}+3 \hat{k}\) is rotated through an angle θ and doubled in magnitude, then it becomes \(4 \hat{i}+(4 x-2) \hat{j}+2 \hat{k}\). The value of \(\mathbf{x}\) is
- \(\left\{-\frac{2}{3}, 2\right\}\)
- \(\left\{\frac{1}{3}, 2\right\}\)
- \(\left\{\frac{2}{3}, 0\right\}\)
- {2, 7}
Answer
(A) - 2 3 , 2
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