Let a and b be two equal vectors inclined at an angle θ, then 2.5 in 9 2 is equal to :

Mathematics · JEE Main · NTA Exams — Vector Algebra

1. \(\frac{|\overrightarrow{\mathbf{a}}-\overrightarrow{\mathbf{b}}|}{2}\)
2. \(\frac{|\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}|}{2}\)
3. \(|\overrightarrow{\mathbf{a}}-\vec{b}|\)
4. \(|\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}|\)

Answer

(A) | a - b | 2

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