Let a = i +2 j +4 k , b = i + j +4 k and c =2 i +4 j + (k^ 2 -1 ) k be coplanar vectors…
Mathematics · JEE Main · NTA Exams — Vector Algebra
Let \(\overrightarrow{\vec{a}}=\widehat{i}+2 \widehat{j}+4 \widehat{k}, \vec{b}=\widehat{i}+\lambda \widehat{j}+4 \widehat{k}\) and \(\vec{c}=2 \hat{i}+4 \hat{j}+\left(k^{2}-1\right) \hat{k}\) be coplanar vectors. Then the non-zero vector \(\vec{a} \times \vec{c}\) is:
- \(-10 \hat{i}-5 \hat{j}\)
- \(-10 \hat{i}+5 \hat{j}\)
- \(-14 \hat{i}+5 \hat{j}\)
- \(-14 \hat{i}-5 \hat{j}\)
Answer
(D) -14 i -5 j
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