Let a and b be two equal vectors inclined at an angle θ, then 2 is equal to :
Mathematics · JEE Main · NTA Exams — Vector Algebra
Let \(\scriptstyle{\vec{\mathbf{a}}}\,\mathbf{and}\,{\vec{\mathbf{b}}}\) be two equal vectors inclined at an angle θ, then \(\sin \frac{\theta}{2}\) is equal to :
- \(\frac{\frac{1}{2}|\overrightarrow{\mathbf{a}}-\overrightarrow{\mathbf{b}}|}{|\overrightarrow{\mathbf{a}}|}\)
- \(\frac{\frac{1}{2}|\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}|}{|\overrightarrow{\mathbf{a}}|}\)
- \(|\overrightarrow{\mathbf{a}}-\vec{b}|\)
- \(|\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}|\)
Answer
(A) 1 2 | a - b | | a |
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