A particle is moving along a straight-line path and its displacement (x) at time t is…
Physics · JEE Main · NTA Exams — Kinematics
A particle is moving along a straight-line path and its displacement (x) at time t is given by
x2 = at2 + 2bt + c (where a, b and c are constants)
the acceleration of the particle is:
x2 = at2 + 2bt + c (where a, b and c are constants)
the acceleration of the particle is:
- \(\frac{\mathbf{a}}{\mathbf{x}}\)
- \(\frac{(a t+b)^{2}}{x^{3}}\)
- \(\frac{a}{x}-\frac{(a t+b)^{2}}{x^{3}}\)
- \(\frac{a}{x}+\frac{(a t+b)^{2}}{x^{3}}\)
Answer
(C) a x - (a t+b)^ 2 x^ 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The velocity of a particle is v = v o + gt + ft 2 . If it’s position is x = 0 at t = 0, then its displacement…
- Find the total displacement of a body in 8 s starting from rest with an acceleration of 20 cm/s2:
- A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the…
- Find range of projectile on the inclined plane which is projected perpendicular to the inclined plane with…
- A body moves 6 m north, 8 m east and 10m vertically upwards, what is its resultant displacement from initial…
- Assertion: Straight line motion is the natural tendency of the body. Reason: Motion in a straight line is an…
- A particle is projected at 60° to the horizontal with a kinetic energy ( K = 1 2 mu ^ 2 ) . The kinetic…
- Two bodies are projected with the same speed. If one is projected at an angle of 30o and the other at an…