A particle is projected at 60° to the horizontal with a kinetic energy ( K = 1 2 mu ^ 2 )…
Physics · JEE Main · NTA Exams — Kinematics
A particle is projected at 60° to the horizontal with a kinetic energy \(\left(\mathrm{K}=\frac{1}{2} \mathrm{mu}^{2}\right)\). The kinetic energy at the highest point is
- K
- zero
- \(\frac{K}{4}\)
- \(\frac{K}{2}\)
Answer
(C) K 4
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