An inclined plane is making an angle with horizontal. A projectile is projected from the…
Physics · JEE Main · NTA Exams — Kinematics
An inclined plane is making an angle \(\beta\) with horizontal. A projectile is projected from the bottom of the plane with a speed u at an angle \(\alpha\) with horizontal then its maximum range \(\mathbf{R}_{\max }\) is
- \(R_{\operatorname{mix}}=\frac{u^{2}}{g(1-\sin \beta)}\)
- \(R_{\operatorname{mx}}=\frac{u^{2}}{g(1+\sin \beta)}\)
- \(R_{\max }=\frac{u}{g(1-\sin \beta)}\)
- \(R_{\max }=\frac{u}{g(1+\sin \beta)}\)
Answer
(B) R_ mx = u^ 2 g(1+ )
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