A projectile is projected with initial velocity (6 i +8 j ) m / sec . If g = 10 ms –2 …
Physics · JEE Main · NTA Exams — Kinematics
A projectile is projected with initial velocity\((6 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}) \mathrm{m} / \mathrm{sec} .\) If g = 10 ms–2, then horizontal range is
- 4.8 metre
- 9.6 metre
- 19.2 metre
- 14.0 metre
Answer
(B) 9.6 metre
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