The velocity of a particle is v = v o + gt + ft 2 . If it’s position is x = 0 at t = 0…
Physics · JEE Main · NTA Exams — Kinematics
The velocity of a particle is v = vo + gt + ft2. If it’s position is x = 0 at t = 0, then its displacement after unit time (t =1) is
- \(v_{0}+2 g+3 f\)
- \(v_{0}+\frac{g}{2}+\frac{f}{3}\)
- \(v_{0}+g+f\)
- \(v_{0}+\frac{g}{2}+f\)
Answer
(B) v_ 0 + g 2 + f 3
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