The position vector of a particle F as a function of time is given by: R =4 (2 t) i +4 (2…
Physics · JEE Main · NTA Exams — Kinematics
The position vector of a particle \(\overrightarrow{\mathrm{F}}\) as a function of time is given by:
\(\vec{R}=4 \sin (2 \pi t) \hat{\hat{i}}+4 \cos (2 \pi t) \hat{\hat{j}}\)
Where R is in meters, t is in seconds and \(\text { i }\) and \(\text { j }\) denote unit vectors along x and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?
- Path of the particle is a circle of radius R meter
- Acceleration vectors is along \(\text { —家 }\)
- Magnitude of acceleration vector is \(\frac{V^{2}}{R}\) where v is the velocity of particle
- Magnitude of the velocity of particle is 8 meter/second
Answer
(D) Magnitude of the velocity of particle is 8 meter/second
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Two bullets are fired simultaneously, horizontally and with different speeds from the same place. Which…
- The displacement of body is given to be proportional to the cube of time elapsed. The magnitude of the…
- A river is flowing from east to west at a speed of 5 m/min. A man on south bank of river, capable of swimming…
- For , , 0 , if ^ -1 + ^ -1 + ^ -1 = and ( + + )( - + )=3 , then equals
- A body falls from rest, its velocity at the end of first second is (g = 32 ft/sec 2 )
- If A B = E A , then the angle between A and B is
- A particle is thrown upward with a speed u at an angle θ with the horizontal. When the particle makes an…
- A body falls from rest in the gravitational field of the earth. The distance travelled in the fifth second of…