( ^ -1 3 5 + ^ -1 5 13 + ^ -1 33 65 ) is equal to :
Physics · JEE Main · NTA Exams — Kinematics
\(\cos \left(\sin ^{-1} \frac{3}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{33}{65}\right)\) is equal to :
- 1
- 0
- 32/65
- 33/65
Answer
(A) 1
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