The gravitational force between two objects is proportional to 1/R (and not as 1/R 2 )…
Physics · JEE Main · NTA Exams — Gravitation
The gravitational force between two objects is proportional to 1/R (and not as 1/R2) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to
- \(\frac{1}{R^{2}}\)
- R0
- R1
- \(\frac{1}{R}\)
Answer
(B) R0
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