If the gravitational force between two bodies were proportional to 1/R (instead of 1/R 2…
Physics · JEE Main · NTA Exams — Gravitation
If the gravitational force between two bodies were proportional to 1/R (instead of 1/R2) where R is the separation between them. then a particle in circular orbit under such a force would have its orbital speed proportional to
- \(\frac{1}{\mathrm{R}^{2}}\)
- \(\frac{1}{\mathrm{R}}\)
- R6
- independent of R
Answer
(D) independent of R
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