(2 ^ -1 1 5 + ^ -1 5 2 +2 ^ -1 1 8 ) is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
\(\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)\) is equal to
- 1
- 2
Answer
(B) 2
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