The value of ( _ n=1 ^ 19 ^ -1 (1+ _ p=1 ^ n 2 p ) ) is
Mathematics · JEE Main · NTA Exams — Trigonometry
The value of \[\cot \left(\sum_{n=1}^{19} \cot ^{-1}\left(1+\sum_{p=1}^{n} 2 p\right)\right) \text { is }\]
Answer
(D)
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