A tower stands at the centre of a circular park. A and B are two points on the boundary…
Mathematics · JEE Main · NTA Exams — Trigonometry
A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (=a) subtends an angle of 60° at the foot of the tower and the angle of elevation of the top of the tower from A or B is 30°. The height of the tower is
- \(\frac{2 \mathrm{a}}{\sqrt{3}}\)
- \(2 a \sqrt{3}\)
- \(\frac{\mathrm{a}}{\sqrt{3}}\)
Answer
(C) a 3
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