If 3 sin θ – 5 cos θ = a, then 5 sin θ + 3 cos θ is equal to
Mathematics · JEE Main · NTA Exams — Trigonometry
If 3 sin θ – 5 cos θ = a, then 5 sin θ + 3 cos θ is equal to
- 1 – a
- \(\sqrt{1-\mathrm{a}^{2}}\)
- \(\sqrt{34-\mathrm{a}^{2}}\)
- \(\sqrt{34-\mathrm{a}^{2}} \text { or }-\sqrt{34-\mathrm{a}^{2}}\)
Answer
(D) 34- a ^ 2 or - 34- a ^ 2
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