A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point…
Mathematics · JEE Main · NTA Exams — Trigonometry
A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird is :
- \(20(\sqrt{3}-1)\)
- \(40(\sqrt{2}-1)\)
- \(40(\sqrt{3}-\sqrt{2})\)
- \(20 \sqrt{2}\)
Answer
(A) 20( 3 -1)
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