If 0 ≤ x ≤ , then the solution of equation 16^ ^ 2 x +16^ 104^ 2 x =10 is given by x…
Mathematics · JEE Main · NTA Exams — Trigonometry
If 0 ≤ x ≤ \(\pi\), then the solution of equation \(16^{\sin ^{2} x}+16^{104^{2} x}=10\) is given by x equal to
- \(\pi\) / 3, \(\pi\) / 6
- \(\pi\) / 3, \(\pi\) / 2
- \(\pi\) / 6, \(\pi\) / 2
- None of these
Answer
(A) / 3, / 6
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