The van der Waals’ constants of a gas are a = 0.751 dm 6 atm mol –2 b = 0.0226 dm 3 mol…
Chemistry · JEE Advanced · NTA Exams — States of Matter (Gases and Liquids)
The van der Waals’ constants of a gas are
a = 0.751 dm6 atm mol–2 b = 0.0226 dm3 mol–1
Hence,
a = 0.751 dm6 atm mol–2 b = 0.0226 dm3 mol–1
Hence,
- VC = 0.678 dm3 mol–1
- VC = 0.0678 dm3 mol–1
- PC = 54.5 atm
- TC = 120 K
Answer
(B) V C = 0.0678 dm 3 mol –1, (C) P C = 54.5 atm, (D) T C = 120 K
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