The electric field strength due a uniformly charged ring of radius R at a distance x from…
Physics · JEE Main · NTA Exams — Electrostatics
The electric field strength due a uniformly charged ring of radius R at a distance x from its centre on its axis carrying charge has somewhere maximum value on the axis. This is at distance
- x = R
- \(x= \pm \sqrt{2} R\)
- \(x= \pm \frac{R}{\sqrt{2}}\)
- \(x= \pm \sqrt{3} R\)
Answer
(C) x= R 2
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