Two parallel plate capacitors of capacity C and 2C are connected in parallel and charged…
Physics · JEE Main · NTA Exams — Electrostatics
Two parallel plate capacitors of capacity C and 2C are connected in parallel and charged to a potential difference V. The battery is then disconnected and the space between the plates of the capacitor C is completely filled with a material of dielectric constant K.
The final potential difference across the capacitors is
- \(\frac{3 V}{(K+1)}\)
- \(\frac{V}{(K+z)}\)
- \(\frac{K V}{(3 K+1)}\)
- \(\frac{3 V}{(K+Z)}\)
Answer
(A) 3 V (K+1)
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