Two free charges q and 4q are placed at a distance d apart. A third charge Q is placed…
Physics · JEE Main · NTA Exams — Electrostatics
Two free charges q and 4q are placed at a distance d apart. A third charge Q is placed between them at a distance x from charge q such that the system is in equilibrium. Then,
- Q = –4q/9, x = d/3
- Q = –4q/9, x = d/4
- Q = –4q/3, x = d/3
- Q = –4q/3, x = d/4
Answer
(A) Q = –4q/9, x = d/3
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