Two free charges q and 4q are placed at a distance d apart. A third charge Q is placed…

Physics · JEE Main · NTA ExamsElectrostatics

Two free charges q and 4q are placed at a distance d apart. A third charge Q is placed between them at a distance x from charge q such that the system is in equilibrium. Then,
  1. Q = –4q/9, x = d/3
  2. Q = –4q/9, x = d/4
  3. Q = –4q/3, x = d/3
  4. Q = –4q/3, x = d/4

Answer

(A) Q = –4q/9, x = d/3

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