If the electric flux entering and leaving an enclosed surface respectively is _ 1 and _ 2…
Physics · JEE Main · NTA Exams — Electrostatics
If the electric flux entering and leaving an enclosed surface respectively is \(\Phi_{1}\) and \(\Phi_{2}\), the electric charge inside the surface will be
- \(\left[\Phi_{1}-\Phi_{2}\right] \epsilon_{a}\)
- \(\left(\Phi_{2}-\Phi_{1}\right] \epsilon_{a}\)
- \(\frac{\left[\Phi_{1}-\Phi_{2}\right]}{\epsilon_{0}}\)
- \(\frac{\left[\Phi-\Phi_{1}\right]}{\epsilon_{a}}\)
Answer
(B) ( _ 2 - _ 1 ] _ a
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