An electric dipole is placed at an angle of 30° with an electric field intensity 2 10^ 5…
Physics · JEE Main · NTA Exams — Electrostatics
An electric dipole is placed at an angle of 30° with an electric field intensity \(2 \times 10^{5} \mathrm{~N} / \mathrm{C}\). It experiences a torque equal to 4Nm. The charge on the dipole, if the dipole length is 2 cm, is:
- 5 mC
- 7 \(\mu\)C
- 8 mC
- 2 mC
Answer
(D) 2 mC
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