When an AC source of emf ε = E 0 sin(100 t ) is connected across a circuit, the phase…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
When an AC source of emf ε = E0 sin(100t) is connected across a circuit, the phase difference between the emf e and the current i in the circuit is observed to be π/4, as shown in the diagram. If the circuit consists possibly only of R-C or R-L or L-C in series, find the relationship between the two elements.
- R = 1 kW , C = 10 mF
- R = 1 kW , C = 1 mF
- R = 1 kW , L = 10 H
- R = 1 kW , L = 1 H
Answer
(B) R = 1 k W , C = 1 m F
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