A rectangular loop with a sliding conductor of lenght l is located in a uniform magnetic…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
A rectangular loop with a sliding conductor of lenght l is located in a uniform magnetic field perpendicular to the plane of the loop. The magnetic induction is B. The conductor has a resistance R. The sides AB and CD have resistances R1 and R2, respectively. Find the current through the conductor during its motion to the right a constant velocity v.
- \(\frac{\mathrm{B} \ell \mathrm{v}\left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)}{\mathrm{R}_{1}\left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)}\)
- \(\frac{\mathrm{B} \ell^{2} \mathrm{v}}{\mathrm{R}_{1}+\mathrm{R}_{1} \mathrm{R}_{2}}\)
- \(\frac{\mathrm{B} \ell \mathrm{v}\left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)}{\mathrm{R}_{1} \mathrm{R}_{2}+\mathrm{R}\left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)}\)
- \(\frac{\mathrm{B} \ell^{2} \mathrm{v}}{\mathrm{R}_{1} \mathrm{R}_{2}+\mathrm{R}\left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)}\)
Answer
(C) B v ( R _ 1 + R _ 2 ) R _ 1 R _ 2 + R ( R _ 1 + R _ 2 )
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