A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 2 m/s in a…

Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 2 m/s in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 µF is connected as shown in figure. Then

1. q_A = + 80 µC and q_B = – 80 µC
   
2. q_A = – 80 µC and q_B = + 80 µC
3. q_A = 0 = q_B
4. Charge stored in the capacitor increases exponentially with time

Answer

(A) q A = + 80 µ C and q B = – 80 µ C

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