A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A & D is
- 0
- 1.41 volt
- 0.71 volt
- None of the above
Answer
(B) 1.41 volt
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