A motor cyclist moving with a velocity of 72 km per hour on a flat road takes a turn on…
Physics · JEE Main · NTA Exams — Rotational Motion
A motor cyclist moving with a velocity of 72 km per hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 metres. The acceleration due to gravity is 10 m/s2. In order to avoid skidding, he must not bend with respect to the vertical plane byan angle greater than-
- θ = tan–1 (6)
- θ = tan–1 (2)
- θ = tan–1 (25.92)
- θ = tan–1(4)
Answer
(B) θ = tan –1 (2)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A particle moves in a circle of a radius 30 cm. Its linear speed is given by : v = 2t, where t in second and…
- A particle moves in a circle of radius 25 cm at two revolutions per second. The acceleration of particle in…
- A solid cylinder of mass 2 kg and radius 4 cm rotating about its axis at the rate of 3 rpm. The torque…
- A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv 2 /r…
- A particle of mass m = 5 units is moving with a uniform speed v=3 2 ~m / s in the XOY plane along the line…
- One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moments of…
- A 6 kg ball starts from rest and rolls down a rough gradual slope until it reaches a point 80 cm lower than…
- A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The…
More Rotational Motion questions · Browse all practice questions