A body of mass m is moving in a circle of radius r with a constant speed v. The force on…
Physics · JEE Main · NTA Exams — Rotational Motion
A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv2/r and it is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?
- \(\frac{\mathrm{mv}^{2}}{\mathrm{r} \times \pi \mathrm{r}}\)
- zero
- \(\frac{\mathrm{mv}^{2}}{\mathrm{r}}\)
- \(\frac{\pi r^{2}}{m v^{2}}\)
Answer
(B) zero
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