A block of mass m slides down along the surface of the bowl from the rim to the bottom as…

Physics · JEE Main · NTA Exams — Rotational Motion

A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The velocity of the block at the bottom will be-

1. \(\sqrt{\pi \mathrm{Rg}}\)
2. 2 \(\sqrt{\pi \mathrm{Rg}}\)
3. \(\sqrt{2 R g}\)
4. \(\sqrt{\mathrm{gR}}\)

Answer

(C) 2 R g

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