If z 1 , z 2 are any two complex numbers, then :

Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations

1. |z₁ + z₂| ≥ |z₁| + |z₂|
2. |z₁ + z₂| > |z₁| + |z₂|
3. |z₁ + z₂| ≤ |z₁| + |z₂|
4. |z₁ + z₂| = |z₁| + |z₂|

Answer

(C) |z 1 + z 2 | ≤ |z 1 | + |z 2 |

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• If a,b,c are distinct real numbers then the equation (b-c) x^ 2 +(c-a) x+(a-b)=0 has
• If roots of the quadratic equation a 1 x 2 + b 1 x + c 1 = 0 are II 1 , 1 and those of a 2 x 2 + b 2 x + c 2…
• The number of solutions for the equation x^ 2 -5|x|+6=0 is/are:
• Given below are two statements. STATEMENT - 1 (Assertion): If 5 z_ 2 11 z_ 1 is purely imaginary then, | 2 z_…
• If for real a, b, c, d,(a+i b)^ [+i d is real, then it is equal to :
• The value of a for which one root of the quadratic equation (a 2 – 5a + 3) x 2 + (3a – 1) x + 2 = 0 is twice…
• If the sum of the squares of the roots of the equation x^ 2 -( x-2) x-(1+ x)=0 is least, then II is
• The equation (x - a) 3 + (x - b) 3 + (x - c) 3 = 0 has

More Complex Numbers and Quadratic Equations questions · Browse all practice questions