The equation (x - a) 3 + (x - b) 3 + (x - c) 3 = 0 has
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The equation (x - a)3 + (x - b)3 + (x - c)3 = 0 has
- all the roots are real
- one real and two imaginary roots
- three roots namely x = a, x = b, x = c
- none of these
Answer
(A) all the roots are real
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let z be a complex number such that | z-1 z+2 i |=1 and |z|= 5 2 . Then the value of | z + 3 i| is :
- If A, G and H are respectively AM, GM and HM of three positive numbers a, b and c, then equation whose roots…
- If ( 1+ i 1- i )^ x =1, then
- If 3+2 i 1-2 i is purely imaginary then θ is
- The principal amplitude of (sin 40 o + i cos 40 o ) 5 is
- If z is any complex number such that z+ 1 z =1, then the value of z^ 99 + 1 z^ 99 is
- If α and β are roots of the equation, x 2 –4 kx + 2e 4 ln k - 1 = 0 for some k, and then is equal to . Find…
- The inequality |z-4|<|z-2| represents the region given by
More Complex Numbers and Quadratic Equations questions · Browse all practice questions