If 3+2 i 1-2 i is purely imaginary then θ is
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If \(\frac{3+2 i \sin \theta}{1-2 i \sin \theta}\) is purely imaginary then θ is
- \(\text { חו TRS }\) + \(\pi / 6\)
- \(\pi-\pi / 6\)
- \(\text { חו TRS }\)
- \(n \pi+(-1)^{n}\left( \pm \frac{\pi}{3}\right)\)
Answer
(D) n +(-1)^ n ( 3 )
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