Figure shows a uniform rod of length l and mass M which is pivoted at end A such that it…
Physics · JEE Main · NTA Exams — Rotational Motion
Figure shows a uniform rod of length l and mass M which is pivoted at end A such that it can rotate in a vertical plane. The free end of the rod ‘B’ is initially vertically above the pivot and then released. As the rod rotates about A, its angular acceleration when it is inclined to horizontal at angle θ is
- \(\frac{3 g}{2 \ell} \cos \theta\)
- \(\frac{g}{\ell} \tan \theta\)
- \(\frac{5 g}{4 \ell} \sin \theta\)
- \(\frac{g}{\ell} \sin \theta\)
Answer
(A) 3 g 2
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