Figure shows a hemisphere of radius 4R. A ball of radius R is released from position P…
Physics · JEE Main · NTA Exams — Rotational Motion
Figure shows a hemisphere of radius 4R. A ball of radius R is released from position P. It rolls without slipping along the inner surface of the hemisphere. Linear speed of its centre of mass when the ball is at position Q is:
- \(\sqrt{\frac{30 g R}{7}}\)
- \(\sqrt{\frac{24 g R}{5}}\)
- \(\sqrt{\frac{40 g R}{9}}\)
- \(\sqrt{6 g R}\)
Answer
(A) 30 g R 7
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