For a transistor, in a common-emitter arrangement, the AC current gain β is given by :
Physics · JEE Main · NTA Exams — Electronic Devices
For a transistor, in a common-emitter arrangement, the AC current gain β is given by :
- \(\beta=\left(\Delta I_{c} / \Delta I_{B}\right)_{v_{c}=\text { constant }}\)
- \(\beta=\left(\Delta I_{B} / \Delta I_{c}\right)_{v_{c}=\text { constant }}\)
- \(\beta=\left(\Delta I_{c} / \Delta I_{c}\right)_{v_{c}=\text { constant }}\)
- \(\beta=\left(\Delta I_{e} / \Delta I_{c}\right)_{v_{c}=\text { constant }}\)
Answer
(A) = ( I_ c / I_ B )_ v_ c = constant
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Carbon is more resistive than germanium and silicon. Then, order of energy gap is :
- Symbol of a p-n junction diode is an arrow, its direction indicates :
- In forward bias, forward current obtained from the p-n junction diode is :
- A transistor is operated in common emitter configuration at constant collector voltage V c = 1.5 V, such that…
- Current in the circuit shown here is (assume diodes are ideal):
- When germanium is doped with phosphorus, the doped material has :
- Due to diffusion of electrons from n to p-side, I. electron-hole combination across p-n junction occurs. II…
- The difference in the variation of resistance with temperature in a metal and a semiconductor arises…
More Electronic Devices questions · Browse all practice questions