In the given figure vertices of ∆ ABC lie on y = f (x) = ax 2 + bx + c. The ∆ ABC is…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
In the given figure vertices of ∆ ABC lie on y = f (x)
= ax2 + bx + c. The ∆ ABC is right angled isosceles triangle whose hypotenuse AC = \(4 \sqrt{2}\) units, then
Number of integral value of k for which \(\frac{\mathrm{k}}{2}\) lies between the roots of f (x) = 0, is
- 9
- 10
- 11
- 12
Answer
(C) 11
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