The value of ^ -1 9+ cosec ^ -1 ( 41 4 ) is given by:
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
The value of \(\cot ^{-1} 9+\operatorname{cosec}^{-1}\left(\frac{\sqrt{41}}{4}\right)\) is given by:
- 0
- \(\frac{\pi}{4}\)
- \(\tan ^{-1} z\)
- \(\frac{\pi}{2}\)
Answer
(D) 2
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