A solid sphere of mass m is lying at rest on a rough horizontal surface. The coefficient…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A solid sphere of mass m is lying at rest on a rough horizontal surface. The coefficient of friction between the ground and sphere is m. The maximum value of F, so that the sphere will not slip, is equal to
- \(\frac{7}{5} \mu m g\)
- \(\frac{4}{7} \mu m g\)
- \(\frac{5}{7} \mu m g\)
- \(\frac{7}{2} \mu m g\)
Answer
(D) 7 2 m g
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