A particle P will be in equilibrium inside a hemispherical bowl of radius 0.5 m at a…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A particle P will be in equilibrium inside a hemispherical bowl of radius 0.5 m at a height 0.2 m from the bottom when the bowl is rotated at an angular speed
( g = 10 m/sec2)
( g = 10 m/sec2)
- 10 / \(\sqrt{3}\) rad/sec
- 10 \(\sqrt{3}\) rad/sec
- 10 rad/sec
- \(\sqrt{20}\)rad/sec
Answer
(A) 10 / 3 rad/sec
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