Two persons A and B are located in X - Y plane at the points (0, 0) and (0, 10)…
Physics · NEET · NTA Exams — Kinematics
Two persons A and B are located in X-Y plane at the points (0, 0) and (0, 10), respectively. (The distances are measured in MKS units). At a time t=0, they start moving simultaneously with velocities
and\(\bar{v}_{B}=\hat{2} m s^{-1},\) respectively. The time after which A and B are at their closest distance is [EAMCET 2009]
and\(\bar{v}_{B}=\hat{2} m s^{-1},\) respectively. The time after which A and B are at their closest distance is [EAMCET 2009] - 2.5 s
- 4 s
- 1 s
Answer
(D)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Two seconds after projection, a projectile is traveling in a direction inclined at 30^ to the horizontal…
- A particle moves along a straight line such that its displacement at any time t is given by 5= [t^ 3 -6 t^ 2…
- A body with mass 5 kg is acted upon by a force F =(-3 i +4 j ) N . If its initial velocity at t = 0 is u =(6…
- A car is circulating on the path of radius r and at any time its velocity is v and rate of increase of…
- y component of velocity is 20 and x component of velocity is 10 The direction of motion of the body with the…
- A particle moves in the X-Y plane under the influence of a force such that its linear momentum is , where A…
- A ball is projected horizontally with a velocity of 5 m/s from the top of a building 19.6 m high. How long…
- A 100 m sprinter increases her speed from rest uniformly at the rate of 1 m/s 2 up to three quarters of the…