A car is circulating on the path of radius r and at any time its velocity is v and rate…
Physics · NEET · NTA Exams — Kinematics
A car is circulating on the path of radius r and at any time its velocity is v and rate of increase of velocity is 'a'. The resultant acceleration of the car will be
- \(\sqrt{\frac{v^{2}}{a^{2}}+r^{2}}\)
- \(\sqrt{\frac{v^{2}}{r}+a}\)
- \(\sqrt{\frac{v^{4}}{r^{2}}+a^{2}}\)
- \(\left(\frac{v^{2}}{r}+a\right)\)
Answer
(C) v^ 4 r^ 2 +a^ 2
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