The locus of the point of intersection of tangents to the parabola y^ 2 =4(x+1) and y^ 2…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The locus of the point of intersection of tangents to the parabola \(y^{2}=4(x+1) \text { and } y^{2}=8(x+2)\) which are perpendicular to each other, is
- \(x+7=0\)
- \(x-y=4\)
- \(x+3=0\)
- \(y-x=12 a\)
Answer
(C) x+3=0
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