The equation 16x 2 – 3y 2 – 32x + 12y – 44 = 0 represents a hyperbola

Mathematics · JEE Main · NTA ExamsCo-ordinate Geometry

The equation 16x2 – 3y2 – 32x + 12y – 44 = 0 represents a hyperbola
  1. the length of whose transverse axis is\(4 \sqrt{3}\)
  2. the length of whose conjugate axis is 4
  3. whose centre is (–1, 2)
  4. whose eccentricity is\(\sqrt{\frac{19}{3}}\)

Answer

(D) whose eccentricity is 19 3

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