The equation 16x 2 – 3y 2 – 32x + 12y – 44 = 0 represents a hyperbola
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation 16x2 – 3y2 – 32x + 12y – 44 = 0 represents a hyperbola
- the length of whose transverse axis is\(4 \sqrt{3}\)
- the length of whose conjugate axis is 4
- whose centre is (–1, 2)
- whose eccentricity is\(\sqrt{\frac{19}{3}}\)
Answer
(D) whose eccentricity is 19 3
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