A geostationary satellite orbits around the earth in a circular orbit of radius 36000 km…
Physics · JEE Main · NTA Exams — Gravitation
A geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then, the time period of satellite orbiting a few hundred kilometres above the earth’s surface (Rearth = 6400 km) will approximately be
- \(\frac{1}{2} h\)
- 1 h
- 2 h
- 4 h
Answer
(C) 2 h
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A satellite is moving around the earth in a stable circular orbit. Which one of the following statements will…
- Radius of orbit of satellite of earth is R. Its Kinetic energy is proportional to:
- The height of the point vertically above the earth’s surface at which the acceleration due to gravity becomes…
- A body is released from a height equal to the radius (R) of the earth. The velocity of the body when it…
- Suppose the gravitational force varies inversely as the n th power of distance. Then the time period of a…
- A body of mass m placed on earth surface is taken to a height of h = 3R, then change in gravitation potential…
- If suddenly the gravitational force of attraction between the Earth and a satellite revolving around it…
- A body of mass m is raised to a height h above the surface of the earth of mass M and radius R until its…